Search by category:

# Area of a Polygon – Learn with Examples

-Whenever we talk about geometry, we speak about side sizes, angles and also areas of the forms. We saw the other two before, let’s talk about the last. You reached numerous questions in the mathematics exam about locating the shaded area of a particular polygon.

For that, you require to have an understanding of solutions of area for various sort of polygons.

What is implied by the area of a poly-gon?

Precisely how to locate a poly-gon Area, including the area of a regular and irregular polygon?

### What is the Area of a Polygon?

In geometry, Area is specified as the region busy inside the border of a two-dimensional number. Hence, the polygon area is the general area or area bound by the sides of a polygon.

The standard system for the dimension of the area is square meters (m2).

#### How to Find the Area of a Polygon?

Regular polygons such as rectangular shapes, squares, trapeziums, parallelograms etc., have pre-defined solutions for calculating their areas.

Nonetheless, for an irregular polygon, the area is computed using partitioning an irregular polygon into small areas of regular polygons.

## Area of a regular polygon

Calculating a regular polygon Area can be as essential as discovering the area of a regular triangular. Regular polygons have equivalent side sizes and also an equal measure of angles.

There are three methods of determining the area of a regular polygon. Each approach is utilized in different events.

Polygon area utilizing the principle of the apothem

The Area of a regular polygon can be calculated using the idea of apothem. The apothem is a line segment that joins the polygon’s center to the midpoint of any side that is perpendicular to that side. Therefore, the Area of a regular polygon is provided by;

A = 1/2. p. a.

Where p = the border of the polygon = amount of all the side lengths of a polygon.

a = apothem.

If the apothem, a = x as well as the length of each side of the government is s, next the area of the pentagon is given by;

Area = 1/2. p. a.

Perimeter = s + s + s + s + s.

= 5s.

So, alternative.

Area = ( 1/2) 5sx.

= (5/2) (s. x) Sq. units.

#### When making use of the apothem method, the length of the apothem will continuously be provided.

Area of a polygon making use of the formula: A = (L2 n)/ [4 tan (180/n)] Additionally, the area of Area polygon can be calculated using the adhering to a formula.

A = (L2 n)/ [4 tan (180/n)]

Where A = area of the polygon.

L = Size of the side.

n = Number of sides of the offered polygon.

Area of a circumscribed poly-gon

The polygon’s area circumscribed in a circle is offered by,

A = [n/2 × L × √ (R ²– L ²/ 4 )]

Square devices. Where n = variety of sides.

L =Side length of a polygon

R = Span of the circumscribed circle.

Let’s work out a couple of instance troubles regarding the Area of a regular poly-gon.

### Example 1

Discover the area of a regular hexagon whose apothem is 10 √ 3 centimetres and also the side length is 20 centimeters each.

Solution

Area = 1/2

First, discover the boundary of the hexagon.

p = (20 + 20 + 20 + 20 + 20 + 20) centimeters = (20 centimeters * 6).

= 120 centimeters.

Substitute.

Area = 1/2.

= 1/2 * 120 * 10 √ 3.

= 600 √ 3 cm2.

### Example 2

Find the Area of a standard hexagon, each of whose sides measures 6 m.

Solution

For a hexagon, the variety of sides, n = 6

L = 6 m

A = (L2n)/ [4tan(180/n)]

By substitution,

A = (62 6)/ [4tan (180/6)]

= (36 * 6)/ [4tan (180/6)]

and, = 216/ [4tan (180/6)]

= 216/ 2.3094

A = 93.53 m2

### Calculate the Area of uneven polygon

An irregular polygon includes interior angles of different degrees. The side sizes of an irregular polygon are likewise of various measure.

As said before, the Area of an irregular poly-gon can be calculated by subdividing an irregular poly-gon right into tiny areas of regular polygons.

### Example

Find the Area of an uneven poly-gon revealed below if, Abdominal Muscle = ED = 20 cm, BC = CD = 5cm as well as Abdominal Muscle = BD = 8 centimeters

Solution

Partition the irregular polygon into areas of regular polygons\

Consequently, ABED is a rectangle and also BDC is a triangle.

Area of rectangular shape = l * w.

= 20 * 8 = 160 cm2.

Area of the triangle = 1/2. b. h.

The height of the triangle can determine using the Pythagoras theory. As an example.

c2 = a2 + b2.

252 = a2 + 42.

a = √ (25– 16).

And, a = 3.

A = 1/2 bh = 1/2 * 3 * 8.

= 6 cm2.